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3+9p=6p^2
We move all terms to the left:
3+9p-(6p^2)=0
determiningTheFunctionDomain -6p^2+9p+3=0
a = -6; b = 9; c = +3;
Δ = b2-4ac
Δ = 92-4·(-6)·3
Δ = 153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{153}=\sqrt{9*17}=\sqrt{9}*\sqrt{17}=3\sqrt{17}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-3\sqrt{17}}{2*-6}=\frac{-9-3\sqrt{17}}{-12} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+3\sqrt{17}}{2*-6}=\frac{-9+3\sqrt{17}}{-12} $
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